### Discussion :: Cube and Cuboid - Cube and Cuboid 2 (Q.No.4)

- Cube and Cuboid - Introduction
- Cube and Cuboid - Cube and Cuboid 1
- «« Cube and Cuboid - Cube and Cuboid 2
- Cube and Cuboid - Cube and Cuboid 3
- Cube and Cuboid - Cube and Cuboid 4
- Cube and Cuboid - Cube and Cuboid 5
- Cube and Cuboid - Cube and Cuboid 6
- Cube and Cuboid - Cube and Cuboid 7
- Cube and Cuboid - Cube and Cuboid 8
- Cube and Cuboid - Cube and Cuboid 9

The following questions are based on the information given below:

- There is a cuboid whose dimensions are 4 x 3 x 3 cm.
- The opposite faces of dimensions 4 x 3 are coloured yellow.
- The opposite faces of other dimensions 4 x 3 are coloured red.
- The opposite faces of dimensions 3 x 3 are coloured green.
- Now the cuboid is cut into small cubes of side 1 cm.

Roshan said: (Nov 7, 2011) | |

Can someone explain it more clearly ? |

Dhana said: (Jan 9, 2012) | |

I did not understand. |

Gaurav said: (Sep 28, 2013) | |

For red 2 from top and 2 from bottom. For green 1 from side and 1 from backside. For yellow 2 from front and 2 from back. Therefore, 4+2+4=10. |

Rahim said: (Dec 2, 2014) | |

Can we use any formula? |

Sabiar said: (May 12, 2016) | |

Anybody give me the actual formula to solve this problem. |

Mahesh said: (Nov 21, 2016) | |

The new l,b,h is (L-2),(b-2),(h-2), then perform lb +bh+hl. After that multiply by 2 for this question new l,b,h after subtracting it from 2 is, 2, 1, 2....2 * 1 + 1 * 1 + 1* 2 = 5 multiply it by two (5 * 2 = 10 ans). |

Alina said: (Dec 13, 2017) | |

We can simplify it as; 5 [(l-2). (b-2) +(b-2). (h-2)+(h-2). (l-2)] . *this formula is applied only if the small cube formed has its side as unity. |

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