Welcome to the DCC!
If you have any questions or comments, feel free to post in the DCC Discussion Thread.
How To Play
How does this card-making game work? It's simple! Whenever your card receives a vote, you receive [1] point for the month. If your card ends up with the most votes for that day, you will receive [2] additional points for the month. In the event of a tie, each person who tied receives [1] additional point. At the end of each month, the person with the most points on the scoreboard wins that month, then the scoreboard is cleared for the next month. You can participate in as many or as few days as you want in any month.
Rules
- Each day you may post any card you want. On the next day all of the posted cards will be put into the thread as long as your card didn't get disqualified - see the next point for more details. If you post more than one card in a DCC thread, only the first card you post will be taken.
- When you vote, you need to make exactly two votes for two different people. Vote for the cards that are listed in the first post, not other cards being posted in the thread. If you notice that you've only voted for one person, include your second vote in a post, even if you're not submitting a card.
- If you want to change your vote for any reason, post that change in the day's thread (you can include it with your card if you want). Changed votes in the discussion thread will be ignored.
- Voting for only one person, for three or more people, or for yourself will earn you an asterisk by your name in the monthly leaderboard. So will failing to vote if you've posted a card. (We're not going to do anything about people who don't vote or post cards; that would be kind of silly.) This indicates that you're on probation for the next 21 days. If you're on probation and you make another improper vote, your card will be disqualified. Repeated disqualification is grounds for warnings and/or infractions for not following the game rules, so please don't do it.
- Voting for everything in the poll will be grounds for a lifetime ban from the DCC. Don't do it. It just wastes the thread creators' time.
- If you wish to post a render, please use the hyperlink option when posting your card and make the card name the image link. Renders are usually large enough to clog up the list, so submit a text-formed card and (optionally) a link in the name to the render.
- This thread is just for your card submission. Take your questions/comments to our discussion thread. If it's a question, comment, or complaint about probation, PM void_nothing and/or the month's DCC organizer.
- When posting make sure that:
- You have included all of the previous day's entries.
- You update the leaderboard with the previous day's scores.
Notes of the Day
Now then, today we will show that the power set of any set, no matter its cardinality, always has a greater cardinality than the original set. Honestly, this proof is really slick.
So, remember back at the beginning of the month, when I was first introducing the idea of a set? I mentioned that any description of a set is valid, even nonsensical ones. It's just that nonsensical descriptions end up with sets that have nothing in them. However, an empty set is still a set. In fact, the empty set is a subset of every single possible set.
So, armed with this fact, let's suppose we have a bijection "f" from a set A to its power set P(A). Then we can define a subset of A as { all "a" in A, such that a is not in f(a) }. This is a subset of A, and thus an element of P(A). We've assumed that f is a bijection, so there should exist a "b" in A such that f(b) is this subset. But is "b" an element of this subset? If it is, then it isn't, by the definition of the set. If it isn't, then it is, by the definition of the set.
So, this subset can't be empty, but it also can't have anything in it. This construction is more-than-nonsensical, and so we must have made a mistake somewhere. But the only thing we really assumed is that f is bijective. Thus, no such bijection can exist. Meanwhile, you can always have an injection that takes a particular element to the subset containing just that one element, and so the cardinality of P(A) is always larger than the cardinality of A.
DCC Scoreboard
netn10 60(+2)
Rithaniel 53 (+2)
Sagharri 52
Riria 47 (+2)
void_nothing 44 (+5)
bravelion83 34 (+1)
Zemoo 21
Ink-Treader 12
Rithaniel 53 (+2)
Sagharri 52
Riria 47 (+2)
void_nothing 44 (+5)
bravelion83 34 (+1)
Zemoo 21
Ink-Treader 12
netn10 wrote: ↑2 years agoVotes: Riria, void_nothing
Disqait Perfectionist
Creature - Vedalken Rogue (Common)
Whenever Disqait Perfectionist enters the battlefield, ransom target creature, artifact or enchantment an opponent control. (Exile it. Its owner may pay at any time to return it to their hand.)
The crime family Disqait specialized in precise assassination, data extraction and kidnaps.
2/2
bravelion83 wrote: ↑2 years agoVotes: void_nothing, Rithaniel
Apprentice Soldier
Creature — Human Soldier (U)
Whenever Apprentice Soldier deals 2 or more combat damage to an opponent, transform it.
Eager to learn...
1/1
Experienced Soldier
( ) Creature — Human Soldier (U)
First strike, vigilance
... eager to fight.
2/2
void_nothing wrote: ↑2 years agoVotes: netn10, Riria
Rite of the Elephant Graveyard
Enchantment (R)
When Rite of the Elephant Graveyard enters the battlefield, create X green Elephant creature tokens with "This creature's power and toughness are each equal to the number of creature cards in its controller's graveyard."
Creature tokens you control have lifelink and menace.
Rithaniel wrote: ↑2 years agoVotes: bravelion83, void_nothing
Wrath of the Elder
Sorcery U
You may sacrifice a Sage creature token rather than pay this spell's mana cost.
Wrath of the Elder deals 3 damage to each creature without flying.
"The old ways are remembered here, because they object to being forgotten."
—Cassa Khho, the Wildling